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prove that
Эx(P(x)^Q(x)) →Э(x)P(x) ^Э(x)Q(x) is a tautology .
Hi dheeraj;
this is a conditional statment which is true except when the condition is true and the result is false(i.e the statment p⇒q is always true except when p is true and q is false ) , but this case does not hold since when Эx(P(x)^Q(x)) is true means that Э(x)P(x) ^Э(x)Q(x) is true too . Therefore Эx(P(x)^Q(x)) →Э(x)P(x) ^Э(x)Q(x) is a tautology .is a tautology .
Best Regards
Riad Zaidan
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