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i have some trouble proving this vector question:
The points A,B,C,D have position vectors a, b, c, d with respect to the origin O. The position vector m, of M on AC such that xAM=yMC, where x+y=1.
Show that if A,B,C,D are points on a sphere, centered at O, and if AC meets BD at M, where x¹BM=y¹MD with x¹+y¹=1, then
xy|a-c|²=x¹y¹|b-d|²
(bolded letters are vectors)
Last edited by wcy (2005-08-07 17:33:09)
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can someone pls help me with this question, i am stuck at it for weeks
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