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Hi
I am stuck on this question
1) When an object is projected upwards from ground level, with initial speed 40 m/s, the height it is above ground t seconds later is h metres where h is given by: h ≈ 40t - 5t^2
State the value of h when the object hits the ground again and find the value of t then.
Thank you
Last edited by Karn (2009-12-30 22:17:06)
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When the object hits the ground again h = 0.
To find the value of t at that time, solve:
But when t = 0 represents the time it is launched, so the value of t when it lands is 8.
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