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∫dx/√x -1
any help would be great.
thanks in advance
.
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∫dx/√x -1
any help would be great.
thanks in advance
sorry if it wasn't clear but the square root is only on the x
Hi chocoholic4lyf;
Please use brackets to communicate what you want. It confused Jane and soroban and confused me too.
You write this indefinite integral like this:
∫ dx / (√(x) -1)
Say x = u^2
dx = 2 u du
Now substitute:
Can you do it now?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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thank you and next time i will. this helped a lot because i did integration by substitution but couldnt get plus root x and kept getting 2rootx times.
Hi chocoholic4lyf;
What are you now getting for the final answer?
To Jane and soroban;
Just realized I phrased my point incorrectly, I didn't mean that either of you were confused, that is not what I meant. I meant that the way the problem was written caused a misinterpretation. Please pardon me for being vague.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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hey bobbym
im now gettinf 2[ln((√x)-1)- (√x) +c]
Hi chocoholic4lyf;
You have a slight error in that integration, please check your work again. If you still don't see it then post your steps.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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