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finitehelp

Member

Registered: 2009-06-21

Posts: 80

Please Help Calculus

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Last edited by finitehelp (2010-02-23 15:51:59)

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Please Help Calculus

Hi finitehelp;

What are the critical values for the function y= e^(x^2-5)?

2) First graph the function:

http://www.mathsisfun.com/graph/functio … ymax=4.546

The graph is suggestive of a minimum at x = 0. Let's verify that.

Get the derivative:

Set it to 0:

Solve for x:

x = 0; check by substitution in the equation. From eyeballing the graph we know that we are dealing with a minimum. (0,0) is a critical point. Else use the side point method or take the second derivative to verify that it is a minimum.

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In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

finitehelp

Member

Registered: 2009-06-21

Posts: 80

Re: Please Help Calculus

thanks bobbym. ny help on the other on question 1 and 3. i kinda had an idea on question 2