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A rubber ball weighing 0.06 kg is dropped on the ground from a height of 1.2 m. After colliding with the ground, the ball rises to a height of 0.3 m .Assuming that the ball was in contact with the ground for 0.01 second,calculate the force exerted by the ball on the ground.
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- David O. McKay
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Well that is more physics than math
Here is the formula you will be using to solve the question:
Ft=p; F=force, t=time, p=momentum or mv (mass times velocity)
* note that we will really be talking about average Force during the collision and the change in momentum over that time period (impulse)
Ft=mv=p
F=p/t
The v (velocity) just before impact and just after impact needs to be found first.
Veloctiy at impact is found by using:
Now to find the velocity just after leaving the ground
Finding delta v and multiplying this to the mass will give us the p we were looking for:
Plugging p into our origianl impluse equation
This is the average force that occurs during contact with the ground.
Hope that helps.
Last edited by irspow (2010-05-20 23:26:48)
I am at an age where I have forgotten more than I remember, but I still pretend to know it all.
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Is it possible to solve this using the general laws of motion or using Newton's law??? or any other easy way???
"Let us realize that: the privilege to work is a gift, the power to work is a blessing, the love of work is success!"
- David O. McKay
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