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This is Theorem 5.2
Let V be a vector space and let W be a nonempty subset of V. Then w is a subspace of V if and only if the following conditions hold:
a. If u and v are in W, then u + v is in W.
b. If u is in W and c is a scalar, then cu is in W.
Now for the question:
In exercise 25, use Theorem 5.2 to determine whether W is a subspace of V.
Can someone please explain to me what is going on here, thanks (if it makes a difference the column vector above is also ment to have squigly brackets around it, but i couldnt do that AND the parenthesis.)
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Nevermind i think i've got it, I'll post my solution tomorrow.
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Solution:
is a nonempty set because it contins the zero vector 0.(i.e. Let)
Let u and v be in
Say,
and
Then
So u+v is also in
(because it has the right form)Siilarly if k is a scalar, then
So ku is in
Thus,
is a nonempty set of that is closed under addition and scalar multiplication. Therefore, is a subspace of , by Theorem 5.2Last edited by samuel12 (2010-07-22 08:09:31)
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