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Hey everyone yet again, I have a really hard triple integral that I need help on.
My working:
But then to integrate with respect to y is very tricky for me, I can get it by calc but it is big and I want to know how to do it by hand.
Any help would be nice.
Thanks
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Could you just change the integration order to
y->x->z ?
X'(y-Xβ)=0
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Could you just change the integration order to
y->x->z ?
I just tried that and it wont work, I get an integral that the calculator wont even do,
I think a different coordinate system needs to be used, but I still can't get it.
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Hi nha;
Why are you certain this one can be done?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi nha;
Why are you certain this one can be done?
It is a textbook question.
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Hi;
What textbook, do you remember?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi;
What textbook, do you remember?
Nah, from a while back but I wrote out the question in my book. Might have been stewarts.
EDIT: would converting to polars work?
Last edited by nha (2010-09-10 15:49:19)
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If it doesn't look like it can be solved I must have written it out wrong.
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Don't worry about it, I give up. I must have written it wrong. Sorry for wasting your time all.
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Hi nha;
You haven't wasted my time. I have been trying with computers to answer your question just to see if it can be done. I managed to coax some answer out of them but I do not understand it.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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In cylindrical coordinates:
x = r cos θ
y = r sen θ
z = z
x² + y² + r²
_____
√x + y = r
Solve this:
pi 4 r/4
∫ ∫ ∫ (2z/r) r dz dr dθ
° ° °
all right?
Zainix
Hi Zainix;
Welcome to the forum. Your idea is fine but I think your substitutions are incorrect. Your answer is (4 / 3 ) π which is not correct for that triple integral.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Is the upper and lower bounds a error?
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