Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 2010-10-09 04:28:03

wednesday
Member
Registered: 2010-09-18
Posts: 7

Mathematical Induction

Hi, I could use some help with this ...

1/2+3/2²+...+(2n-1)/2^n=1+2(1-1/(2^(n-1))-(2n-1)/2^n

Last edited by wednesday (2010-10-09 04:36:03)


It is possible to store the mind with a million facts and still be entirely uneducated.

Offline

#2 2010-10-09 08:56:08

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

Re: Mathematical Induction

Hi wednesday;

Is your problem stated like this?

What are you trying to do? Prove it by induction?
Or use the summation calculus as someone already has, to get the RHS?

I will try by induction first:

The base step when n = 1, 1/2 = 1/2 , okay.

To shorten the algebra I am going to use a little notational trickery on the right hand side.

If that is true and the next is true we will have a proof by induction. The next is

we can replace most of the LHS by 1).

Can you finish from here? It is all algebra but you will find RHS = LHS.

So proved by induction.

You know summing the series by direct methods such as the summation calculus and the Euler Mclaurin summation formula would be a proof and probably easier.


In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

Offline

Board footer

Powered by FluxBB