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Hi guys, I have a mechanics question on what I think is dynamics.
A particle P of mass 2 kg is acted on by two forces
And
(a) Show that the acceleration of P is
Which we do with
At time t = 0 P is at the point with position vector
Relative to a fixed origin O and has velocity
Calculate at time t = 3 seconds
(b) The velocity of P
Which is:
(c) The position vector of P
Here is where I am stuck. Does anybody have any suggestions? Thanks.
Last edited by Au101 (2011-03-18 14:22:27)
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Fnet=(6i+2j)
anet={Fnet/2}=(3i+j)........Ans
Vx=V(initial)+ax*t
4+3*3=13
Vy=0+3*1=3
Vnet=Vxi+Vyj
(13i+3j).........Ans
X=X0+v(initial)*t+1/2*ax*t^2
=2+4*3+1/2*3*9
=27.5
Y=Y0+0+1/2*1*9
=-1+4.5
=3.5
="hence requried position vector=(27.5i+3.5j)".........Ans
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Aha, got it. Thanks Sameer
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