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Let G be a group with subgroups K and H where H is cyclic, H is normal in G and K is normal in H. Show that K is normal in G.
We want to show that gkg^(-1) ∈ K for all k ∈ K and g ∈ G. I know gkg^(-1)=gh^nkh^(-n)g^(-1) where h^n=1. I know the solution probably involves some combination of those elements but I can't quite see how. Does anyone have a clearer idea?
Thanks!
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