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I'm really confused on problems with square roots... Can someone please explain to me how to do this problem? It would be greatly appreciated. ^_^ I'm sure it's something simple, but I'm so confused.
√1+sinθ/1-sinθ = 1+sinθ/|cosθ|
<3Angel~
Swimming through sick lullabies, Choking on your alibis...
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hi yaz angel!!
what does "<3" in your signature mean??? i see that expression being used a lot lately.
(1+sinθ)^(1/2) (1+sinθ)
------------------ = ----------- the left side is easier to work with
(1-sinθ)^(1/2) |cosθ|
(1+sinθ)^(1/2)
------------------ multiply everything by the "conjugate" of the denominator
(1-sinθ)^(1/2)
(1+sinθ)^(1/2)*(1+sinθ)^(1/2) (1+sinθ)^(2/2) 1+sinθ
------------------------------------ = ------------------------------ = ------------------
(1-sinθ)^(1/2)*(1+sinθ)^(1/2) [(1-sinθ)(1+sinθ)]^(1/2) (1-sin²θ)^(1/2)
1+sinθ
------------------ remember the identity cos²θ = 1-sin²θ
(1-sin²θ)^(1/2)
1+sinθ 1+sinθ
------------------ = ---------------- since √a ≥ 0, then √cos²θ > 0 ⇒ |cosθ|
(cos²θ)^(1/2) (cosθ)^(2/2)
1+sinθ 1+sinθ
--------- = ---------
√cos²θ |cosθ|
Last edited by Flowers4Carlos (2005-11-14 16:18:57)
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Omg... Thank you so much for your help. ^_^ It is greatly appreciated....
And <3 is just a symbol for a heart... I use it more than I should, really... But oh well.
Thanks again!!
<3Angel~
Swimming through sick lullabies, Choking on your alibis...
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ahhh... a heart! yes i recognize those!! they are the ones that are always fluttering about chris evans.
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Gee, good work there Flowers.
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
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