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Hello Forum, after i find the solution to this equation 5m+10=8m-2, how do i check to make sure the answer is correct. Greatly appreciate any help!
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Hi TryingMyBest50;
Welcome to the forum.
Subtract 5m from both sides.
Add 2 to both sides.
Divide both sides by 3.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi bobbym, i first need to say that math is not my subject. With that said, is that how i check that the solution is a true statement?
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hi TryingMyBest50
Welcome to the forum.
And then check by working out if 5x4 + 10 gives the same result as 8x4 -2
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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You check by substituting the 4 into the m.
5 x 4 = 20 and 8 x 4 = 32
20 + 10 = 30 and 32 - 2 = 30
Checked and you are done.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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hi bobbym
how are you today?
That latex error was strange. \times (4) worked for me in a preview.
Test
curious
Maybe it's all in the spaces?
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Hi Bob;
I am fine, how is everything?
Until it gets into the cache, some latex will not work. It is functioning okay now.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi bob, i want to thank both you and bobbym for your feed back. So i just replace the answer with what ever letter is presented to check my that the sollution is correct, right?
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Replace the letter ( variable ) that you solved for and do the arithmetic correctly. Both sides should be the same.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Variable, i knew the letter had a name i just coudln't think of it. Thank you so much for your help! You guy's are great! Have a Blessed day!
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You are welcome.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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hi bobbym,
While your latex was producing an error I copied it so I could check the ascii codes of your symbols. Then when that revealed nothing I did my test post 6. And your original latex is still there producing an error. So I don't think it's a cache problem.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Hi Bob;
On mine it is working fine. Does it look like this for you?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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hi bobbym,
Yes, it does.
But look at post 6
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Hi;
Sorry, I did not see that.
Removing the spaces causes it to work.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Oh yes. But this is still weird for me:
Wont work version: 5 \times (4)+10 = 8 \times (4)-2
De-spaced version works: 5 \times (4)+10=8 \times (4)-2
But my working version had loads of spaces:
5 \times (4) + 10 = 8 \times (4) -2
Just got to put my head in some ice. Back later.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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That is true. I can remove one space and everything is fine.
Just got to put my head in some ice.
Sounds cooling!
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi guy's it's me again. How do i turn this linear equation 4x+11=6x-3 into an linear inequality? Would i write it like 4x<+11=6x<-2, and the lesser sign is underlined?
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Hi;
I have never heard of that...
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi Bobbym, I need to change the linear equation 4x+11=6x-3 into a linear inequality (using < or >). Can it be done?
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Why couldn't you just replace the = with a < or a >?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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ok, so how would you solve the equation using < or >.
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Which one?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I need to turn this linear equation 4x+11=6x-3 into a linear inequality.
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4x+11<6x-3 or 4x+11>6x-3 or 4x+11≤ 6x-3 or 4x+11 ≥ 6x-3
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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