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Find a general solution to
y′′′ − y′′ + 2y = 0
I have never dealt with 3rd order D.E before. I hope you have!
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(1/12)y^4 = (1/2)y^2 - y + (1/2)C[1]y^2 + C[2]y - C[3]
Is that the answer?
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'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'
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@Agnishom;
These are solved using the characteristic or auxiliary polynomial or try this:
DSolve[{y'''[x] - y''[x] + 2 y[x] == 0}, y[x], x]
Hi mrpace;
Here is a so-so explanation:
http://www.math.upenn.edu/~moose/240S20 … es8-05.pdf
The auxiliary equation is
and the roots are:
r1 = -1
r2 = 1 + i
r3 = 1 - i
can you finish now?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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