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Hi! I'm pretty stamped on what to do in a problem my teacher gave us.
See, the nth term is given, however, what the n is, is not.
For example:
1+2+4+8+...+65536
where a is 1
d is 2
last term is 65536
Now my problem is how do I get the n in
X(sub n) ?
I have the X, but I don't know the n. Help?
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hi LittleBear
Welcome to the forum.
This sequence is called geometric. Each term is double the one before.
The formula for the nth term is
where a = 1 and r = 2.
It's not too hard to just go on doubling and counting how many times. But, when the numbers get tricky you can also use logs:
On a calculator you'll find a log button and also a natural log button (ln). You can use either provided you use the same button for both logs.
http://www.mathsisfun.com/algebra/expon … ithms.html
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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