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Ok so I was just brushing up algebra skills for the test next week and I ran in a bump with this problem.
2. The perimeter of a rectangle is 48m. The width of the rectangle is 2 more than half the length. Find length and width.
So I set up these 2 equations
2l+2w=48
and
2w-4=l
(solved from w=l/2+2)
and got this
2(2w-4)+2w=48
4w-8+2w=48
6w-8=48
6w=56
w=28/3
Is this wrong because all the awnsers said they were integers..?
Last edited by Mathegocart (2016-01-26 11:16:22)
The integral of hope is reality.
May bobbym have a wonderful time in the pearly gates of heaven.
He will be sorely missed.
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Hi;
That is what I got too.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Can you list the answer choices? I am getting 28/3 too.
Could it be an answer choice error?
Last edited by evene (2016-01-26 12:37:59)
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Length is 44/3 and width is 28/3.
If the width is supposed to be THREE more than half the length you get 14 and 10. Besides that I can't see a simple adjustment to make integers
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