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Circle
intersects the hyperbola at , and two other points. What is the product of the y coordinates of the other two points?Offline
Is that Circle called Gamma?
What did you get for an answer? Did you have a guess?
Did you draw an accurate graph of the problem? Here is one possible solution.
Does that give you an idea? Is it possible to have all 4 points in the first quadrant?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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{1}Vasudhaiva Kutumakam.{The whole Universe is a family.}
(2)Yatra naaryasthu poojyanthe Ramanthe tatra Devataha
{Gods rejoice at those places where ladies are respected.}
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Thank you so much!
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hi dazzle,
Have you realized there are infinite number of circles meeting the criterion but product of y coordinates remaining constant?
{1}Vasudhaiva Kutumakam.{The whole Universe is a family.}
(2)Yatra naaryasthu poojyanthe Ramanthe tatra Devataha
{Gods rejoice at those places where ladies are respected.}
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yup, I understand that!
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Why is the equation of the circle different from what I got when I expanded (x – h)^2 + (y – k)^2 = r^2?
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What did you do?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi;
Why is the equation of the circle different from what I got when I expanded (x – h)^2 + (y – k)^2 = r^2?
It is an equation of a circle at a point (h,k). If you want an circle at the origin [(0,0)] then h and k are both 0 and hence the equation is x^2-y^2=r^2.
Practice makes a man perfect.
There is no substitute to hard work
All of us do not have equal talents but everybody has equal oppurtunities to build their talents.-APJ Abdul Kalam
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Oh..oh I'm sorry.
Practice makes a man perfect.
There is no substitute to hard work
All of us do not have equal talents but everybody has equal oppurtunities to build their talents.-APJ Abdul Kalam
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