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1. Compute the angle at C of the triangle ABC if the altitudes at A and B intersect each other at an angle measuring 60◦. Consider all possibilities.
2. Compute the angle at C of the triangle ABC if the internal angle bisectors at A and B intersect each other at an angle measuring 60◦. Consider all possibilities.
So for 1 I think there is only 1 possibility in that the angle at C is 60 but are there actually more possibilities?
For 2 I think there are two possibilities depending on where the 60 is but I can't seem to figure out what the angle at C should be.
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hi sydbernard
(1) I think it's only one as well. If the altitudes are AD and BE and they meet at G, then DGB = 60 and GDB = 90 implies DBG = 30.
BEC = 90 and CBE = 30 implies BCE (BCA) = 60.
(2) Work in progress.
Later edit: I am unable to draw a diagram for this at all. Let D be where the bisectors cross.
A + B < 180 implies DAB + DBA < 90. Therefore ADB > 90
Do you have a diagram?
Other post: I'm working on a method involving ellipses and circles. If successful I'll post on that thread later. Later edit: Done in other thread.
Bob
Last edited by Bob (2017-11-10 01:13:07)
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