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I am going to list my answers to my geometry homework. The ones I have already answered I need to take the sqrt if there are any perfect squares. The three i left blank I did not know how to answer. I will put the teachers comment down below. Help please I've been stuck for awhile and it needs to be done fast.
11. √108
12. √576
13. question : a=7 and c=SQRT 85
(don't know the answer)
14. √24
15. question : a=1 and c=SQRT 2
(don't know the answer)
16. √44
17. √784
18. √306
19. question : a=6 and c=6(SQRT 2)
(don't know the answer)
20. √23
teacher comments :
The ones you have completed look good... just make sure that if the numbers you get are PERFECT SQUARES... go ahead and take the SQRT.
For #13, 15 and 19... see my previous feedback!!!
previous feedback :
Make sure that you always STATE the final answer... if you end up wth c2 = 4... then c=2 which is the SQRT of 4. Since 4 is a perfect square, you can give it's actual sqrt. IF you were to get something like c2 = 5... your answer would just be c=√5. Since 5 is NOT a perfect square, just leave the answer as a sqrt
Also... make sure that you understand when you SQUARE a SQRT... the operations CANCEL each other out and leave ONLY the number from under the radical!
Ex... √5 2 = √5 * √5 = 5
ex 2.... (2√5)2 = 2*2*√5*√5 = 4*5 = 20
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Do you know how to 'reduce' a number to its prime factors? I'll do
12. √576
as an example.
576 = 2 x 288 = 2 x 2 x 144 = 2 x 2 x 2 x 72 = 2 x 2 x 2 x 2 x 36 = 2 x 2 x 2 x 2 x 2 x 18 = 2 x 2 x 2 x 2 x 2 x 2 x 9 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3
You keep dividing by prime factors until the resulting multiplication is all primes. http://www.mathsisfun.com/prime-factorization.html
Now you can see if the number is a perfect square:
2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 = (2 x 2 x 2 x 3) x (2 x 2 x 2 x 3) = 24 x 24
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
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