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Question: Evaluate i=(integral 0 to 4 ) integral (sqrty to 2) y cox (x)^5 dx dy ?
Why we change dx and dy position and why cox(x)^5 does not solvable?
hi MKNB
Welcome to the forum.
This is not going to be easy.
Start with
When you expand the brackets the first two terms have the presence of a function and its derivative and so are directly integrable; the third is too.
That gives you a way to do the inner integral.
Then substitute y = u^2 and switch the outer integral to one involving du rather than dy. It can be done in a similar way, converting the even powers of sine into cosines and using the function and its derivative method.
Worth switching the outer limits to u limits as the numbers convert easily too.
Good luck. Let me know how you get on.
Later edit:
I gave this a try and the first part worked ok. But the substitution didn't. I've been out all day so haven't had a chance to try anything else. I'll make a fresh post if I do.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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