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Hi everyone! I am new to this website and I need a bit of help with this problem. I do not need you to answer the problem for me, just walk me through a few steps/hints and I will try to solve it on my own.
In triangle ABC, AB = AC, and angle A is equal to 36 degrees. Point D is on line AC so that line BD bisects angle ABC.
(a) Prove that BC = BD = AD.
(b) Let x = BC and let y = CD. Using similar triangles BCD and ABC, write an equation involving x and y.
(c) Let r = \frac{y}{x}. Write the equation from Part (b) in terms of r, and find r.
(d) Find cos(36) and cos(72) using Parts a-c.
This is a problem from the Introduction to Geometry course at Art of Problem Solving.
I should add that I have completed the first three parts, and I am just stuck on part (d). Thank you in advance!
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Rule of math: If it seems easy, you're doing it wrong.
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hi RCKittenLover
Welcome to the forum.
THis has appeared before here:
http://www.mathisfunforum.com/viewtopic.php?id=22416
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Hello! It seems that the link you have given me is from quite a while ago. Should I continue it?
Cats restore sanity
Rule of math: If it seems easy, you're doing it wrong.
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It's the same problem. Looks like your teachers are re-cycling old worksheets.
The posts go on a bit. As you've got to part d, skip to post 11.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Okay, thank you!
Cats restore sanity
Rule of math: If it seems easy, you're doing it wrong.
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