Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**don.farr****Member**- Registered: 2020-11-24
- Posts: 3

A) VL = Δi /Δt

(200*10-6) ((200*10-3)/2*10-6)

0.002 (( 2 ) / 0.00002)

0.002 * 1OOOOO

200V

B) VL = Δi /Δt

(200*1.0e-6) ((200*10-3)/2*10-6)

0.02 (( 2 ) / 0.00002)

0.0002 * 1OOOOO

20V

Where VL = Instant voltage on an inductor

Δi = Change in amperage

Δt – Change in time

The answer given in the textbook is “20 volts” However, using the book’s formula (A) I come up with 200V instead of the answer of 20V

So I created process “B” and I get the correct answer, but I cannot not explain why there is a difference between using the “Micro value (10-6) and using the exponent value 1.0e-6”

*Last edited by don.farr (2021-01-02 07:36:06)*

Offline

**Bob****Administrator**- Registered: 2010-06-20
- Posts: 10,408

hi don.farr

I'm confused in trying to compare your two methods.

In B

(200*1.0e-6)

What does this mean?

1.0 x e^-6 is a different thing altogether. e raised to the power -6 would not be a simple power of ten.

Are you using the 'exp' key on a calculator here. That would make this 1.0 x 10^-6 which makes this the same as A.

Also

0.02 (( 2 ) / 0.00002)

0.0002 * 1OOOOO

Here you have changed 0.02 into 0.0002. I cannot see why.

This physics is not my area but I can substitute values into a formula and evaluate. Please go back a step and say where the values have come from. Then I'll try to see what the correct evaluation is.

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Sometimes I deliberately make mistakes, just to test you! …………….Bob

Offline

**don.farr****Member**- Registered: 2020-11-24
- Posts: 3

Good morning Bob and thanks for your help. Yes I am using the exponent key on a calculator.

No matter how I do this, problem (A) is supposed to resolve to 20A. I get 200A using the equation given in (A)

The textbook equation is give in (A) without any changes. So I ask, what am I doing wrong in my evaluation of the formula? Is it possible that the formula is incorrect or the answer given is incorrect?

Offline

Hi don.farr,

Welcome to the forum. I believe you're missing out a factor of 10 in your multiplication -- note that:

This might help:

I'm getting 20 as the correct answer when I run through your calculation in A. Let us know if you need any more help!

Offline

**don.farr****Member**- Registered: 2020-11-24
- Posts: 3

Got it. I was using the wrong button on the calculator. I was using the exponent button instead of power button. Thanks!!!!!

Offline

Pages: **1**