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In Exercises 9–14, determine the quadrant(s)
in which (x, y) could be located.
My answers are located below each problem.
9. x > 0 and y < 0
Where is x positive and y negative? Quadrant 4.
10. x < 0 and y < 0
Here, x and y are both negative. Quadrant 3.
11. x = −4 and y > 0
This is quadrant 2.
12. x < 0 and y = 7
This is quadrant 2.
13. x + y = 0, x ≠ 0, y ≠ 0
I am not too sure about this one. If y = -x, then x - x = 0.
If x = -y, then -y + y = 0.
14. xy > 0
I know that negative times negative is positive.
I also know that positive times positive is positive.
The only quadrant where both x and y are positive is
quadrant 1. This is my answer.
Is any of this right?
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9-12 all ok.
13. Try plotting this as a straight line. It goes across two quadrants
14. So does this as xy can be positive when both x and y are negative.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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9-12 all ok.
13. Try plotting this as a straight line. It goes across two quadrants
14. So does this as xy can be positive when both x and y are negative.
Bob
Ok. For 13, I say quadrants 1 and 2.
For 14, I say quadrants 1 and 3.
Yes?
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Bob wrote:9-12 all ok.
13. Try plotting this as a straight line. It goes across two quadrants
14. So does this as xy can be positive when both x and y are negative.
Bob
Ok. For 13, I say quadrants 1 and 2.
For 14, I say quadrants 1 and 3.
Yes?
For 14, yes. Try looking at 13 a little closer.
The integral of hope is reality.
May bobbym have a wonderful time in the pearly gates of heaven.
He will be sorely missed.
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mathland wrote:Bob wrote:9-12 all ok.
13. Try plotting this as a straight line. It goes across two quadrants
14. So does this as xy can be positive when both x and y are negative.
Bob
Ok. For 13, I say quadrants 1 and 2.
For 14, I say quadrants 1 and 3.
Yes?
For 14, yes. Try looking at 13 a little closer.
I don't get 13 at all.
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You have identified the equation as y = -x (correct!) so plot the graph.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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You have identified the equation as y = -x (correct!) so plot the graph.
Bob
The graph of y = -x goes through the origin from quadrant 2 down to quadrant 4.
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Excellent! that's what I needed to see.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Excellent! that's what I needed to see.
Bob
Thanks.
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