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Given y = (sec t)/(1 + t sin t), find y prime.
I will not show all my work via cell phone. It takes to long to type all the math work.
Here is where I am:
y' = [(sec t•tan t)(1 + t sint) - sec t•sin t + t sec t cost t]/(1 + t sint)^2
Stuck here....
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You might like to use the fact that:
sec(t)*cos(t) = 1
and
sec(t)*sin(t) = tan(t)
Can you see why these are true?
Let me see. I think using trigonometric identities helps out here.
sec (t) = 1/cos(t).
sec(t)cos(t) becomes 1/cos(t) • cos(t) = cos(t)/cos(t) = 1.
So, sec (t) sin(t) becomes 1/cos(t) sin(t) = sin(t)/cos(t) = tan(t).
The problem now becomes all too clear.
Thanks.
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