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Andrew and Beatrice each have their own savings account. Beatrice’s account has $600 less than three times what Andrew’s account has. If Andrew had $300 more dollars, then he would have exactly half what is currently in Beatrice’s account. How much does Beatrice have?
Let me see.
This problem is more involved.
Let B = Beatrice
Let A = Andrew
B = 3A - 600
A + 300 = (1/2)(B)
Is this the correct system of equations to solve this problem?
You say?
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It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
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Yes, those equations will work. You can most easily eliminate B, hence get A, then work out B.
Check your answer fits the facts.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Thanks. I found out that my equations also lead to the right answer.
Last edited by sologuitar (2023-10-10 01:41:04)
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Yes, those equations will work. You can most easily eliminate B, hence get A, then work out B.
Check your answer fits the facts.
Bob
Ok. Sounds good. Thank you.
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