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Determine which of the given points are on the graph of the equation.
Equation: y = x^3 - 2•sqrt{x}
Points: (0, 0); (1, 1); (1, -1)
I think I need to plug and chug here. If I get the same answer on both sides of the given equation, I can then say that the point is on the graph of the given equation.
Let me see.
Point (0, 0).
y = x^3 - 2•sqrt{x}
0 =(0)^3 - 2•sqrt{0}
0 = 0 - 0
0 = 0
Point (0, 0) is the graph of the equation.
How about Point (1, 1)?
y = x^3 - 2•sqrt{x}
1 = (1)^3 - 2•sqrt{1}
1 = 1 - 2(1)
1 DOES NOT = -1.
I say this point is not on the graph of the equation.
How about the final point (1, -1)?
y = x^3 - 2•sqrt{x}
-1 = (1)^3 - 2•sqrt{1}
- 1 = 1 - 2(1)
- 1 = - 1
Yes, this point is on the graph of the equation.
You say?
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All agreed.
B
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
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All agreed.
B
I must say that this problem is not too bad.
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