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The area of a rectangular window is to be 306 square centimeters.
If the length exceeds the width by 1 centimeters, what are the dimensions of the window?
I think A = length • width is needed here. Yes?
Length = x + 1
Width = x
306 = (x + 1)(x)
(x + 1)(x) = 306
x^2 + x = 306
x^2 + x - 306 = 0
Is this the correct equation?
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The area of a rectangular window is to be 306 square centimeters.
If the length exceeds the width by 1 centimeters, what are the dimensions of the window?I think A = length • width is needed here. Yes?
Length = x + 1
Width = x
306 = (x + 1)(x)
(x + 1)(x) = 306
x^2 + x = 306
x^2 + x - 306 = 0
Is this the correct equation?
solve the eqn and check the sol'ns in the problem
you'lla get 2 sol'ns
ignore the negative sol'n
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harpazo1965 wrote:The area of a rectangular window is to be 306 square centimeters.
If the length exceeds the width by 1 centimeters, what are the dimensions of the window?I think A = length • width is needed here. Yes?
Length = x + 1
Width = x
306 = (x + 1)(x)
(x + 1)(x) = 306
x^2 + x = 306
x^2 + x - 306 = 0
Is this the correct equation?
solve the eqn and check the sol'ns in the problem
you'lla get 2 sol'ns
ignore the negative sol'n
After solving the quadratic equation for x, I got two answers like you said.
x = -18
x = 17
We are talking about distance. So, I reject -18.
Answer: width = 17 centimeters; length = 18 centimeters.
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