You are not logged in.
Pages: 1
Find the intercepts given the equation 5x + 2y = 10.
Let me see.
To find the x-intercept let y = 0.
5x + 2y = 10
5x + 2(0) = 10
5x + 0 = 10
5x = 10 - 0
5x = 10
x = 10/5
x = 2
To find the y-intercept, let x = 0.
5x + 2y = 10
5(0) + 2y = 10
0 + 2y = 10
2y = 10 - 0
2y = 10
y = 10/2
y = 5
The x-intercept is x = 5, which can also be written (5, 0).
The y-intercept is y = 5, which can be also be written (0, 5).
You say?
Offline
Find the intercepts given the equation 5x + 2y = 10.
To find the x-intercept let y = 0.
5x + 2(0) = 10
5x = 10
x = 2
To find the y-intercept, let x = 0.
5(0) + 2y = 10
2y = 10
y = 5
you can check your work by graphing
y = -(5/2)x + 5
Offline
harpazo1965 wrote:Find the intercepts given the equation 5x + 2y = 10.
To find the x-intercept let y = 0.
5x + 2(0) = 10
5x = 10
x = 2
To find the y-intercept, let x = 0.
5(0) + 2y = 10
2y = 10
y = 5
you can check your work by graphing
y = -(5/2)x + 5
Already checked it out.
Offline
Pages: 1