You are not logged in.
Pages: 1
A jumbo chocolate bar with rectangular shape measures 12 cm in length, 7 cm in width, and 3 cm in thickness. Due to escalating costs of cocoa, management decides to reduce the volume of the bar by 10%. To accomplish this reduction, management decides that the new bar should have the same 3 cm thickness, but the length and width of each should be reduced an equal number of centimeters. What should be the dimensions of the new candy bar?
This one through me into a loop.
I think this problem demands the use of the volume formula
V = length • width • height. The part about reducing the volume by 10% is confusing to me.
Can someone explain what is going on in this problem and set up the right equation for me to use?
Offline
A jumbo chocolate bar with rectangular shape measures 12 cm in length, 7 cm in width, and 3 cm in thickness. Due to escalating costs of cocoa, management decides to reduce the volume of the bar by 10%. To accomplish this reduction, management decides that the new bar should have the same 3 cm thickness, but the length and width of each should be reduced an equal number of centimeters. What should be the dimensions of the new candy bar?
This one through me into a loop.
I think this problem demands the use of the volume formula
V = length • width • height. The part about reducing the volume by 10% is confusing to me.Can someone explain what is going on in this problem and set up the right equation for me to use?
old length: 12
old width: 7
old thickness: 3
old volume: ___
new length: 12 - x
new width: 7 - x
new thickness: 2
new volume: ___
new volume is 90% of old volume
Offline
harpazo1965 wrote:A jumbo chocolate bar with rectangular shape measures 12 cm in length, 7 cm in width, and 3 cm in thickness. Due to escalating costs of cocoa, management decides to reduce the volume of the bar by 10%. To accomplish this reduction, management decides that the new bar should have the same 3 cm thickness, but the length and width of each should be reduced an equal number of centimeters. What should be the dimensions of the new candy bar?
This one through me into a loop.
I think this problem demands the use of the volume formula
V = length • width • height. The part about reducing the volume by 10% is confusing to me.Can someone explain what is going on in this problem and set up the right equation for me to use?
old length: 12
old width: 7
old thickness: 3
old volume: ___new length: 12 - x
new width: 7 - x
new thickness: 2
new volume: ___new volume is 90% of old volume
Old volume = 7•12•3 or 252 cm^3
New volume is 2(12 - x)(7 - 2)
A. Where did 12 come from?
B. Where did 7 come from?
C. What must I do with 90%?
Offline
A jumbo chocolate bar with rectangular shape measures 12 cm in length, 7 cm in width, and 3 cm in thickness. Due to escalating costs of cocoa, management decides to reduce the volume of the bar by 10%. To accomplish this reduction, management decides that the new bar should have the same 3 cm thickness, but the length and width of each should be reduced an equal number of centimeters. What should be the dimensions of the new candy bar?
old length: 12
old width: 7
old thickness: 3
old volume: ___new length: 12 - x
new width: 7 - x
new thickness: 3 (same as old thickness)(sry abt typo before)
new volume: ___new volume is 90% of old volume
Old volume = 7•12•3 or 252 cm^3
New volume is 2(12 - x)(7 - 2)
this assumes that x=2
how did you get this?
when you checked your ans did it work out right?
A. Where did 12 come from?
B. Where did 7 come from?
A jumbo chocolate bar with rectangular shape measures 12 cm in length, 7 cm in width,, and 3 cm in thickness.
C. What must I do with 90%?
new volume is 90% of old volume
what is 90% of old volume?
set equal and solve
Offline
harpazo1965 wrote:A jumbo chocolate bar with rectangular shape measures 12 cm in length, 7 cm in width, and 3 cm in thickness. Due to escalating costs of cocoa, management decides to reduce the volume of the bar by 10%. To accomplish this reduction, management decides that the new bar should have the same 3 cm thickness, but the length and width of each should be reduced an equal number of centimeters. What should be the dimensions of the new candy bar?
amnkb wrote:old length: 12
old width: 7
old thickness: 3
old volume: ___new length: 12 - x
new width: 7 - x
new thickness: 3 (same as old thickness)(sry abt typo before)
new volume: ___new volume is 90% of old volume
harpazo1965 wrote:Old volume = 7•12•3 or 252 cm^3
New volume is 2(12 - x)(7 - 2)
this assumes that x=2
how did you get this?
when you checked your ans did it work out right?harpazo1965 wrote:A. Where did 12 come from?
B. Where did 7 come from?
A jumbo chocolate bar with rectangular shape measures 12 cm in length, 7 cm in width,, and 3 cm in thickness.
harpazo1965 wrote:C. What must I do with 90%?
new volume is 90% of old volume
what is 90% of old volume?
set equal and solve
1. I made a typo, obviously.
I meant to say that the new volume is 2(12 - x)(7 -x)
2. The old volume is 252 cm^3. So, 0.90 (252) = 226.8 cm^3.
3. The set up is here:
226.8 = 2(12 - x)(7 - x)
I get two answers for x:
x_1 is approximately-20.67035
We are talking about measurement. So, the value of x_1 must be rejected.
I also know that x_2 is approximately 39.67035. I can round this to be 40.
Dimensions of the new candy bar:
Length = (12 - 40) leads to a negative answer.
Width = (7 - 40) leads to a negative answer.
Height = 2
Something is wrong. The length, width and height must be positive.
What did I do wrong?
Is 226.8 = 2(12 - x)(7 - x) the correct equation needed to find the new length, width and height of the candy bar?
Last edited by sologuitar (2023-11-10 09:43:37)
Offline
This is my method:
Old volume = 12 times 7 times 3
New volume = (12-x)(7-x) times 3
10% reduction means new volume = 0.9 of old volume. So my equation is
I simplified that to a quadratic, found x and checked it led to a 10% reduction. There was a second value from the quadratic which was obviously too big (ie > 12)
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
Offline
This is my method:
Old volume = 12 times 7 times 3
New volume = (12-x)(7-x) times 3
10% reduction means new volume = 0.9 of old volume. So my equation isI simplified that to a quadratic, found x and checked it led to a 10% reduction. There was a second value from the quadratic which was obviously too big (ie > 12)
Bob
Wow! You are definitely talented. Trust me, there are thousands of college students and graduate students who have no idea how to even begin solving this problem. I get confused with the bad wording in most word problems. Thanks for the equation. I can take it from here.
Offline
Pages: 1