You are not logged in.
Pages: 1
Third and final part of the question.
Again, I could work it out, but I’m looking for the proper method.
Trial and error;
1 over suggests a reciprocal, maybe, so a negative 1 might be involved…
Fraction for answer might imply a fractional index…
√3 would mean 2 for the denominator
Try 3^-1/2
= (√3)^-1
= 1/√3
So c=-1/2
Offline
3^c = 1 / √3
3^c = 1 / 3^(1/2)
3^c = 3^(-1/2)
c = -1/2
Last edited by KerimF (2023-12-17 14:25:51)
Offline
I’m looking for the proper method...for 3^c=1/ √3 ?
Remember that sqrt is 1/2 power & flipping is minus
1/sqrt{3}=1/(3^(1/2))=3^{-(1/2)}
so c=-1/2
Always try to convert sides to same base
Then set powers equal and solve - no guessing
Offline
3^c = 1 / √3
3^c = 1 / 3^(1/2)
3^c = 3^(-1/2)c = -1/2
Thanks, KerimF, you've been really helpful.
Offline
paulb203 wrote:I’m looking for the proper method...for 3^c=1/ √3 ?
Remember that sqrt is 1/2 power & flipping is minus
1/sqrt{3}=1/(3^(1/2))=3^{-(1/2)}
so c=-1/2
Always try to convert sides to same base
Then set powers equal and solve - no guessing
Thanks, amnkb
Offline
Pages: 1