You are not logged in.
Pages: 1
Determine if each relation is a function. For each function, state the domain and range.
Question 1
{(-2, 5), (-1, 3), (3, 7), (4, 12)}
Here, no x-value has 2 different values of y.
I say this is a ffunction.
Domain = values of x
Range = values of y
Do you agree?
Question 2
{(-4, 4), (-3, 3), (-2, 2), (-1, 1), -4, 0)}
I say this is not a function because -4 has two different values of y.
You say?
Offline
1. agree that its a fcn
2. agree
Offline
1. agree that its a fcn
2. agree
For the domain, we can also say x-values.
For the range, we can also say y-values.
Look here: (x, y) = (domain, range)
Agree?
Offline
I understand why you might say that. There are some maths courses out there that agree with this idea.
But, according to Wolfram Alpha, domain is defined as "the set of values for the independent variable for which a functioin is defined". x has only been given for a limited set of values so that fixes the domain as {-2, -1, 3, 4}. Range is similarly defined.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
Offline
I understand why you might say that. There are some maths courses out there that agree with this idea.
But, according to Wolfram Alpha, domain is defined as "the set of values for the independent variable for which a functioin is defined". x has only been given for a limited set of values so that fixes the domain as {-2, -1, 3, 4}. Range is similarly defined.
Bob
To me, domain = x and range = y. It's easier to think about it this way.
Offline
Pages: 1