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Determine if each function is even, odd, or neither.
1. f(x) = cuberoot{2x^2 + 1}
f(-x) = cuberoot{2(-x)^2 + 1}
f(-x) = cuberoot{2x^2 + 1}
I say even.
2. h(x) = x/(x^2 - 1)
h(-x) = -x/((-x)^2 - 1)
h(-x) = -x/(x^2 - 1)
I say odd.
3. F(x) = 2x/|x|
F(-x) = 2(-x)/|-x|
F(-x) = -2x/x
F(-x) = -2
Neither even or odd.
You say?
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1 and 2 are correct.
Think again about 3. If x is positive 2x/|x| = 2x/x = 2 If x is negative 2x/|x| = 2x/-x = -2
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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1 and 2 are correct.
Think again about 3. If x is positive 2x/|x| = 2x/x = 2 If x is negative 2x/|x| = 2x/-x = -2
Bob
Understood but this further agrees that the answer is neither.
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Definition:
A function is "odd" when:
−f(x) = f(−x) for all x
In this question f(x) = 2 f(-x) = -2 = -f(x) This is an odd function.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Definition:
A function is "odd" when:
−f(x) = f(−x) for all x
In this question f(x) = 2 f(-x) = -2 = -f(x) This is an odd function.
Bob
Thank you very much.
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