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The slope of the secant line containing the two points
(x, f(x)) and (x + h, f(x + h)) on the graph of a function y = f(x) may be given as
m_sec = [f(x + h) - f(x)]/[(x + h) - x] which leads to [f(x + h) - f(x)]/h, where h cannot = 0.
Express the slope of the secant line for the function f(x) = -x^2 + 3x - 2 in terms of x and h. Be sure to simplify.
Let me see.
f(x) = [-(x + h)^2 + 3(x + h) - 2 -(-x^2 + 3x - 2)/h
f(x) = -(x^2 + 2xh + h^2) + 3x + 3h - 2 + x^2 - 3x + 2)/h
f(x) = (-x^2 - 2xh - h^2 + 3x + 3h - 2 + x^2 - 3x + 2)/h
f(x) = (-2xh - h^2 + 3h)/h
f(x) = -2x - h + 3
You say?
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Looks good.
B
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Looks good.
B
Looks like I totally get the process here. I don't know why Michael Sullivan decided to introduce a calculus topic this early in a college algebra textbook.
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