You are not logged in.
Pages: 1
3 eyed martians met with earthlings (each with 2 eyes) in the first ever intergalactic. observers noticed that there were only 14 people, yet there were 34 eyes. how many of the people are earthlings?
Here's the way I did it, a very non-matimatical way.
Let's assume that everyone is human. Then there are 28 eyes. For every human we replace with a martian, the net gain is 1 eye.
We need to gain 34-28 = 6 eyes, meaning there are 6 martians. Thus, there are 8 humans.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
Offline
Or you could do it the mathmatical way:
3x + 2y = 34 (3 eyes for each martian, 2 for each human, is equal to 34)
x + y = 14 (martians and humans combine to 14 people total)
we need to solve for y, ill choose the second equation and get:
y=-x + 14
Now substitue that in for y in the first equation and simplify:
3x + 2(-x + 14) = 34
3x - 2x + 28 = 34
x = 6
Now since X stands for martians, we know we have 6 martians, leaving us with 8 humans.
If you plug those in for the first equation you will find 3(6) + 2(8) = 34, thus there are:
6 Martians (18 eyes) and 8 (16 eyes) Humans.
Last edited by Dionysus (2006-03-08 17:10:25)
Offline
My way took about 5 seconds
But I also had a feeling kkkkk didn't know how to solve systems of equations yet. But I see no other mathimatical way to do it.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
Offline
3m+2e=34
m+e=14--->2m+2e=28
Therefore, m=6, e=8.
No. of maritans=6, no. of earthlings=8.
(Time taken = about 15 seconds)
This is how I teach my students to approach problems involving Simultaneous equations. Most examinations give about half a minute or less to solve such problems, and I think this is the best way it can be done!
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
Offline
Here's the way I did it, a very non-matimatical way.
Let's assume that everyone is human. Then there are 28 eyes. For every human we replace with a martian, the net gain is 1 eye.
We need to gain 34-28 = 6 eyes, meaning there are 6 martians. Thus, there are 8 humans.
That's not very non-mathematical. It's logical at least, and logic fits in very micely with maths.
It's just a bit unconventional. It's how I'd have done it, though.
Why did the vector cross the road?
It wanted to be normal.
Offline
I got 6 martians and 8 earthlings.
Everyone had 2 eyes at least so that would be 14*2=28 take 28 from 34 and you know that you need 6 martains to equal 34 eyes!? or
Last edited by damathgirl (2006-03-12 05:50:41)
Offline
That works!
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
Offline
Problems that involve martians are always funner.
A logarithm is just a misspelled algorithm.
Offline
I took the question literally:
14 people (humans) = 28 eyes
2 martians = 6 eyes
Offline
Pages: 1