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Factor each polynomial completely. If the polynomial cannot be factored, say it is prime.
Problem 116; page 58.
(5x + 1)^3 - 1
Difference of two cubes formula:
(x - a)(x^2 + ax + a^2)
Let x = 5x and a = 1.
Note: 1 can be written as 1^3.
Apply formula.
(5x - 1)((5x)^2 + 5x + 1)
(5x - 1)(25x^2 + 5x + 1)
You say?
Last edited by mathxyz (2024-05-20 14:37:01)
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Right idea but it went wrong here:
Let x = 5x and a = 1.
That should be "x" = 5x +1. I've put "x" because that x is the one in the cube formula and it's different from the x in the question.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Right idea but it went wrong here:
Let x = 5x and a = 1.
That should be "x" = 5x +1. I've put "x" because that x is the one in the cube formula and it's different from the x in the question.
Bob
Thanks. Let me see.
Let x = 5x + 1
Let a = 1.
Difference of cubes formula:
(x - a)(x^2 + ax + a^2)
(5x + 1 - 1)((5x + 1)^2 +1(5x + 1) + 1^2)
(5x)(25x^2 + 10x + 1 + 5x + 1 + 1)
(5x)(25x^2 + 15x + 3)
It looks a little weird.
Is that it?
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That is indeed it. Problem done!
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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That is indeed it. Problem done!
Bob
Very cool.
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