Math Is Fun Forum

mathxyz

Member

From: Brooklyn, NY

Registered: 2024-02-24

Posts: 1,053

Extra Factor Completely

Factor each polynomial completely. If the polynomial cannot be factored,  say it is prime.

Problem 120; page 58.

x^3 - 3x^2 - x + 3

Group A = x^3 - 3x^2

Group B = -x + 3

Factor both groups.

Group A

x^3 - 3x^2

GCF = x^2

x^2(x - 3)

Group B

GCF = -1

-1(x + 3)

x^2(x - 3) - 1(x - 3)

(x^2 - 1)(x - 3)

(x - 1)(x + 1)(x - 3)

You say?

Bob

Administrator

Registered: 2010-06-20

Posts: 10,627

Re: Extra Factor Completely

Got it! well done.

Bob

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Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob

mathxyz

Member

From: Brooklyn, NY

Registered: 2024-02-24

Posts: 1,053

Re: Extra Factor Completely

Got it! well done.

Bob

It looks like my factoring skills are still there more or less. I feel confident. As you know, factoring is the key to success in algebra.