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Suppose that m and n are positive integers with m > n. If a = m^2 - n^2, b = 2mn, and c = m^2 + n^2, show that a, b and c are the lengths of the sides of a right triangle.
Last edited by Oculus8596 (2024-09-27 02:44:15)
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hi Oculus8596
Welcome to the forum.
opposite integer :- the number that is the same distance from zero but with the opposite sign.
This restriction is unnecessary as the result follows even when m and n are any real numbers.
Start with a^2 + b^2 = (m^2 - n^2)^2 + 4m^2n^2
Continue with the algebra until you reach c^2
Pythagoras theorem works 'in reverse' so a^2 + b^2 = c^2 is sufficent to prove the right angle.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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hi Oculus8596
Welcome to the forum.
opposite integer :- the number that is the same distance from zero but with the opposite sign.
This restriction is unnecessary as the result follows even when m and n are any real numbers.
Start with a^2 + b^2 = (m^2 - n^2)^2 + 4m^2n^2
Continue with the algebra until you reach c^2
Pythagoras theorem works 'in reverse' so a^2 + b^2 = c^2 is sufficent to prove the right angle.
Bob
The algebra is a bit tedious but doable.
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It's just two more lines to the result.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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It's just two more lines to the result.
Bob
(m^2 - n^2)^2 + 4m^2n^2 = c^2
(m^2 - n^2)(m^2 - n^2) + 4m^2n^2 = c^2
m^4 - 2m^2n^2 + n^4 + 4m^2n^2 = c^2
m^4 + 2m^2n^2 + n^4 = c^2
Where do we go from here?
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That's it. In any triangle if a^2 + b^2 = c^2 then you may conclude that the triangle is right angled.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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That's it. In any triangle if a^2 + b^2 = c^2 then you may conclude that the triangle is right angled.
Bob
Wonderful. Work is completed. I thought the right side needed to look like the left side of a^2 + b^2 = c^2.
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