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get A and B which make ( AX + BY ) ² = X (4 Y - 3 X ) + 1 an equation for a circle and then get the centre and the radius .
help please
ImPo$$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...
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A²X²+2ABXY+B²Y²=4XY-3X²+1
(A²+3)X²+(2AB-4)XY+B²Y²=1
∴2AB-4=0 AND A²+3=B² AND CENTER IS (0,0)
X²/P²+Y²/P²=1 WHERE 1/P²=A²+3=B²
X²+Y²=P² SO THE RADIUS IS P
A=2/B, 4/B²+3=B²=DEF=X
4/X+3=X
you can go on from here
X'(y-Xβ)=0
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excuse me can you finish it please ?
it sometimes seems difficult for me to translate that to arabic u know ... sorry everybody for botering
ImPo$$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...
Offline
4/X+3=X
4+3X=X²
(X-4)(X+1)=0
X=4 and radius r=√x=2
center is O, (0,0)
X'(y-Xβ)=0
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thanks man
ImPo$$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...
Offline
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