Math Is Fun Forum

4littlepiggiesmom

Member

Registered: 2006-01-09

Posts: 42

Solving the Equations with Square Roots(SQRT)

(Sqrt)of (3/2X-5) -10=(2/5)

I keep coming up with 6 but I don't think it's the right answer......Any help would be great ! Thanks to all.....
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krassi_holmz

Real Member

Registered: 2005-12-02

Posts: 1,905

Re: Solving the Equations with Square Roots(SQRT)

or

?
you usually solve equations of this kind:

,
by squaring the both sides and assuming that

(we are talking for REAL solutions):

and

Now, consider the first equation:

, which is >0. So for x we get:

Last edited by krassi_holmz (2006-05-14 19:52:31)

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4littlepiggiesmom

Member

Registered: 2006-01-09

Posts: 42

Re: Solving the Equations with Square Roots(SQRT)

Thanks for the help but I used the wrong number after the = sign it should read

(Sqrt)of (3/2X-5) -10=-8 so I get
(sqrt) of (3/2x-5)=2 so then I get
3/2x-5=4 then
3/2x=9 then
3x=18
x=6

Thanks a bunch for the help! K

krassi_holmz

Real Member

Registered: 2005-12-02

Posts: 1,905

Re: Solving the Equations with Square Roots(SQRT)

That's right.

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IPBLE:  Increasing Performance By Lowering Expectations.

4littlepiggiesmom

Member

Registered: 2006-01-09

Posts: 42

Re: Solving the Equations with Square Roots(SQRT)

thanks again!