You are not logged in.
Pages: 1
how to get this lim ?
ImPo$$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...
Offline
It looks like you can use L'Hopital's rule twice; the denominator will be reduced to 2x, then to 2. At that point setting x = 1 in the expression will produce a finite value.
Offline
It looks like you can use L'Hopital's rule twice; the denominator will be reduced to 2x, then to 2. At that point setting x = 1 in the expression will produce a finite value.
You can use L'Hopital once, but after that the denominator will be 2x. It now doesn't equal zero when x equals one. You might be able to do some rearranging, though.
Bad speling makes me [sic]
Offline
Oh yes, indeed, the rule can only be applied once. Then x can be set to 1.
Offline
Bad speling makes me [sic]
Offline
thanks alot guys ... but can you tell me what is this rule '' L'Hopital's rule '' ? maybe i learnt it but i dont know what do they call it in english ... i want more explaination please
ImPo$$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...
Offline
WHAT? Your book asked you this and it didn't teach you L' Hoptials rule?
A logarithm is just a misspelled algorithm.
Offline
its not from my book !
ImPo$$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...
Offline
Actually in my first year calculus course they also gave us limit questions which required L'Hopital's rule but which was not taught yet; I suppose there is some weird other way of doing it but this is the best way!
So here is L'Hopital's Rule for the case of rational functions:
Consider a limit
If f(a)/g(a) gives an *indeterminate form*, such as:
Then you are allowed to differentiate the top and bottom functions:
If this new limit also gives an indeterminate form, you can differentiate the top and bottom again until the quotient gives a 'normal' value.
(The actual definition is more technical and precise, but I think this is sufficient for school assignments )
Offline
i saw it in my book ! we didnt learn that lesson yet !!!
thank you everybody
ImPo$$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...
Offline
oh thank you alot polylog ...
there is no way to solve it without differbtiation ? i meant just with limits and continuity ?!
ImPo$$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...
Offline
There might be, but it's more difficult... I can't think of a way to do it without differentiation.
Offline
thanks again !
ImPo$$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...
Offline
You could always derive L'Hopital's rule from first principles as part of the question. Or guess the answer and use a delta/epsilon proof to show it's correct
Bad speling makes me [sic]
Offline
Pages: 1