# Math Is Fun Forum

Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫  π  -¹ ² ³ °

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## #1 2006-11-28 04:41:40

unique
Member
Registered: 2006-10-04
Posts: 419

### equation

following equation given that 0 <_? < 2pi :

tan2? - sqrt(3) = 0

hi guys help me on this thanks

Desi
Raat Key Rani !

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## #2 2006-11-28 22:40:16

gnitsuk
Member
Registered: 2006-02-09
Posts: 121

### Re: equation

Solution of

is

Where n = {1,2,3.....}

So with your equation we have:

In the range 0° =< 2x <= 720°

So we have:

In the range 0° =< x <= 360°

Last edited by gnitsuk (2006-11-28 22:50:46)

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## #3 2006-11-28 22:44:55

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

### Re: equation

And x = 210[sup]o[/sup], and x = 300[sup]o[/sup].
Edit: Ah, sorry. I should have seen that you were still editing.

Why did the vector cross the road?
It wanted to be normal.

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## #4 2006-11-28 22:46:13

gnitsuk
Member
Registered: 2006-02-09
Posts: 121

### Re: equation

Thanks, I was still editing

That'll teach me not to read my preview thoroughly before submitting

Last edited by gnitsuk (2006-11-28 22:51:42)

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## #5 2006-11-29 03:38:32

unique
Member
Registered: 2006-10-04
Posts: 419

### Re: equation

sorry guys i messed up i had ot write

following equation given that 0 <_theta < 2pi :

tan2(theta) - sqrt(3) = 0

Desi
Raat Key Rani !

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