Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

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**unique****Member**- Registered: 2006-10-04
- Posts: 419

following equation given that 0 <_? < 2pi :

tan2? - sqrt(3) = 0

hi guys help me on this thanks

Desi

Raat Key Rani !

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**gnitsuk****Member**- Registered: 2006-02-09
- Posts: 121

Solution of

is

Where n = {1,2,3.....}

So with your equation we have:

In the range 0° =< 2x <= 720°So we have:

In the range 0° =< x <= 360°*Last edited by gnitsuk (2006-11-28 22:50:46)*

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**mathsyperson****Moderator**- Registered: 2005-06-22
- Posts: 4,900

And x = 210[sup]o[/sup], and x = 300[sup]o[/sup].

Edit: Ah, sorry. I should have seen that you were still editing.

Why did the vector cross the road?

It wanted to be normal.

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**gnitsuk****Member**- Registered: 2006-02-09
- Posts: 121

Thanks, I was still editing

That'll teach me not to read my preview thoroughly before submitting

*Last edited by gnitsuk (2006-11-28 22:51:42)*

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**unique****Member**- Registered: 2006-10-04
- Posts: 419

sorry guys i messed up i had ot write

following equation given that 0 <_theta < 2pi :

tan2(theta) - sqrt(3) = 0

Desi

Raat Key Rani !

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