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How do I write an equation of the line with slope -2 and y-intercept (0,0)?
would it be
y=-2x or y= x -2
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The first one is correct. The slope determines the coefficient that goes before the x term and the y-intercept determines the constant term.
Basically, a line with slope a and y-intercept (0,b) will have the equation y = ax+b.
Why did the vector cross the road?
It wanted to be normal.
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Hi
How did you solve this problem. Can you explain it stepwise pl.
Thanks
S
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Hi
How did you solve this problem. Can you explain it stepwise pl.
Thanks
S
It's just as mathyperson said.
Since the line in question has slope -2 and y-intercept (0,0), so a = -2 and b = 0. Substitute them to the y = ax + b equation and you have:
y = ax + b
y = -2x + 0
y = -2x
Actually I never watch Star Wars and not interested in it anyway, but I choose a Yoda card as my avatar in honor of our great friend bobbym who has passed away.
May his adventurous soul rest in peace at heaven.
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