Math Is Fun Forum

Kiran

Member

Registered: 2006-11-15

Posts: 177

Expandiing

ab/m ( -2m^(-2) / ba  +  3m / a^(-1) b  )

than

ab/m (-2/abm^(2) +  3am/b) < handle negative exponents
ab/m * -2/abm^2 + ab/m * 3am/b < distribute
now i have to do......

---

Live 4 Love

Jai Ganesh

Administrator

Registered: 2005-06-28

Posts: 48,413

Re: Expandiing

Kiran,
If the question was simplifying the expression
ab/m ( -2m^(-2) / ba  +  3m / a^(-1) b  ),
the steps would be
ab/m ( -2m^(-2) / ba  +  3m / a^(-1) b  )
= ab/m[-2/bam²+3am/b]
=[-2ab/bam³+3a²bm/bm]
=-2/m³+3a²
(Cancelling the common factors in the numberators and the denominators)
-2/m³+3a² cannot be simplified any further.

---

It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.