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Last edited by Stanley_Marsh (2007-04-10 10:42:08)
Numbers are the essence of the Universe
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K=odd , this holds, if k= even ,this holds too , then throw n dices , the probability of getting an even sum will be 0.5
Last edited by Stanley_Marsh (2007-04-10 10:42:38)
Numbers are the essence of the Universe
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You could see it this way:
denote nCk = (n choose k)
The Binomial Theorem says
(1+x)^n = summation (k=0 to k=n) nCk(x^k)
Put x=-1: 0 = summation (k=0 to k=n) (-1)^k(nCk)
So sum of odd terms = sum of even terms.
Put x=1 to see both sums are 2^(n-1).
With this we could see the probability questionthis way:
Prob(sum of n dice is odd)
= 1/(2^n) (# of combinations in which an odd number of dice is odd)
= 1/(2^n) (nC1 + nC3 + nC5 + ...)
= 1/(2^n) (2^(n-1))
= 1/2
Similar for the even case.
Thanks.
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My proof works either , I just need to prove the case when n=even
Numbers are the essence of the Universe
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