Math Is Fun Forum

gairceilatan

Member

Registered: 2007-05-22

Posts: 7

Integration Help

Can someone help me with this question?

∫sec^6x dx

I know that ∫sec²x dx = tanx + c but i'm stumped on this one. 

I tried making u=tanx to give du/dx=sec²x then I could not get any further.

I'm sure this is so simple you will laugh but it's driving me nuts

Thank you

JaneFairfax

Member

Registered: 2007-02-23

Posts: 6,868

Re: Integration Help

You use a trick:

gairceilatan

Member

Registered: 2007-05-22

Posts: 7

Re: Integration Help

Hi JaneFairfax,

Thanks for your help can i just double check this is for secx to the power 6 (secx)^6 and not sec6x? 

I don't mean to be cheeky but your answer was not at all what I was expecting as the other questions on my sheet all involved making something = u so we could get du/dx.

Thanks again for your help