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l = r x p for a rotating object
angular momentum = radius times perpendicular momentum
dl/dt = (dr/dt) x p + (dp/dt) x r
The book then says dr/dt equals the instantaneous velocity at that point, but how can the change in distance from the axis of rotation be the same as the change in circular distance?
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r is a vector, not a scalar. If r has a fixed magnitude, its direction will still be changing; hence it still makes sense to talk of the rate of change of r with respect to t (change of direction if not of magnitude).
NB: In the equation l = r × p, × is vector product, not ordinary multiplication. Vector product is only defined for vectors, not scalars.
Last edited by JaneFairfax (2007-10-30 14:02:06)
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Thanks!
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