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A man and a boy agree to dig a patch of potatoes for ten dollars. The man can dig as fast as the boy can pull tops, and he can pull tops twice as fast as the boy can dig. How should the money be divided?
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Let digging be 1 parameter, say x, and pulling tops be another, say y. However, pulling tops is of no use until digging is completed. Hence I think the money should be divided equally. Maybe I am wrong!
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
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Here there is two situation one when the man digs and the boy pulls the top and vice versa.
Man digging= pulling tops by the boy.........1
Boy digging.......2
2(Pulling the top by man).......2
If the first situation that is 1) holds true then the money should be divided equally that is 1:1
If the second situation that is 2) holds true then the money between the man:boy should be 2:1.
Still i have my doubts..please check with other members
Regards
Khushboo
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How they work together on the project is not calculatable from the small amount of evidence given.
igloo myrtilles fourmis
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