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#1 2008-04-16 00:49:29
- EMPhillips1989
- Member
- Registered: 2008-01-21
- Posts: 40
limits
hey i'm stuck on the following question
find the limit if it exists
i think the limit is 0 but i dont know how to prove this can anyone help???
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#2 2008-04-16 01:05:09
- Identity
- Member
- Registered: 2007-04-18
- Posts: 934
Re: limits
As
will get bigger and bigger.Sine is a periodic function, so it will keep repeating itself after a certain value of
The range of the sine function is [-1, 1], so
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#3 2008-04-21 01:13:52
- moxiuming
- Member
- Registered: 2008-04-20
- Posts: 7
Re: limits
since sin(1/x) is bounded so there exist a number M such that |sin1/x|<M,then |x*sin(1/x)|<M|x|
so it approaches 0 as x approaches 0. in fact we can let M=2.
Last edited by moxiuming (2008-04-21 01:16:39)
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