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I'm trying to study Real Analysis and I need a bit of help on a problem. This is number 7 on page 167 of Bartle's and Sherbert's Introduction to Real Analysis, 3rd Edition.
Suppose that
is differentiable at and that . Show that is differentiable at if and only if .Last edited by LampShade (2009-02-22 18:30:42)
-- Boozer
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I think I have a solution, but I'm not sure about my reasoning at the end.
Let
. Then .By the chain rule,
.This implies that
.If
this limit is undefined since .If
, then is defined and is 0.I'm just not sure why
removes the discontinuity created by dividing by .Last edited by LampShade (2009-02-23 13:56:20)
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It is rare that you can use anything from calculus in an analysis class. Typically you are trying to prove results that reach beyond the basic theory. With that in mind, it is never a bad idea to write down precisely what these things means.
Try relating the two. It will be more concrete to use epsilon-delta definitions.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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Ok! I posted this question on Yahoo! answers, and I got a reply there as well. I took Rick's advice and combined it with the reply from Yahoo to get the following. Please let me know if there are any mistakes. Oh, and thanks for the warning about the chain rule!!!
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