Math Is Fun Forum
Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °
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#1 2009-04-04 03:06:34
- sumpm1
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- Registered: 2007-03-05
- Posts: 42
Real Analysis Help
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#2 2009-04-04 04:53:31
- JaneFairfax
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- Registered: 2007-02-23
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Re: Real Analysis Help
For #2, see this post: http://www.mathisfunforum.com/viewtopic … 92#p104692 
Last edited by JaneFairfax (2009-04-04 11:25:15)
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#3 2009-04-05 09:36:19
- sumpm1
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Re: Real Analysis Help
Last edited by sumpm1 (2009-04-05 19:36:49)
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#4 2009-04-05 17:27:48
- Azathoth
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Re: Real Analysis Help
For 1b)
if {Xk}->L and for {Rk}->0, |Xk - Yk|<Rk, then for k≥N, |Xk - L|<e and |Xk - Yk|<e. Thus |Yk - L|=|Yk - Xk + Xk -L|≤|Yk - Xk| + |Xk - L|<e+e=2e
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